We can use the mirror equation
$\begin{align*}\frac{1}{d_0} + \frac{1}{d_i} = \frac{1}{f}\end{align*}$
The focal length $f$ for a convex mirror is half of the distance to the center of curvature and it is negative by convention. So, $f = -R/2$ . If $d_0 = R$ , then
$\begin{align*}d_i = - \frac{R}{3}\end{align*}$
where the negative sign indicates that the image is to the right of the mirror. Also, an image in a convex mirror is always upright. So, answer (E) is correct.

Solution to 2008 Problem 74